There are 3 cars moving at speeds in the ratio of. If the fastest car
covers 10 km more than the car with medium speed in 30 minutes, then the
speed of the slowest car in kmph is...?
Answer:
Let the speeds of the three cars be 1.5y kmph, 2.5y kmph, and 3y kmph.
The fastest car, then, covers 3y/2 km in 30 minutes.
Therefore, the speed of the slowest car is (1.5 × 40) = 60 kmph.
No comments:
Post a Comment